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Exact points formulas?

Posted: Tue Apr 02, 2002 8:04 pm
by Pi
Hello everyone.

I'm on MARP since a year or more, but I'm not too active. I decided to *ehem* reclaim *ehem* my place as *ehem* tetris god *ehem*, but I can't understand yet the scoring system. I know I will not even be in the top 100, but it's all for the fun, right? :) However I don't like to do things I don't understand, and the percent scoring system keeps me dazzled.

The help on that is outdated and/or ambiguous. First, it took me a bit to remember all the meaning of the leaderboard numbers, the help on that is a bit outdated. Then I tried to learn how the percentage scoring works, but totally failed on that. I mean, in bloxeedc, the first place has 396,000 points, I have a third place with 200,000 points, and it gives me 37 pts for the leaderboard. I don't understand the relationship between all those numbers. I know there is a percentage, a 15% less for each position below first, but If anyone can give me an equation I would be grateful.

Thanks in advance and sorry if this has been asked a zillion times, but I haven't find the answer yet.

Posted: Tue Apr 02, 2002 8:21 pm
by gameboy9
Try this one:

100 - (100 - (your score / top score)) * (0.85 ^ (your place - 1))

So 97,400 vs. your 92,000 I think in JoyJoy:

100 - (100 - (92000 / 97400)) * (0.85 ^ 1) = (100 - (5.55)) * (0.85) = 80 points

Posted: Tue Apr 02, 2002 9:32 pm
by Pi
> Try this one:

> 100 - (100 - (your score / top score)) * (0.85 ^ (your place - 1))

Yessss that's it, thank you very much.

> So 97,400 vs. your 92,000 I think in JoyJoy:

Yes that's me, I swear I did 135,000 and I have a partial Kawaks input to prove it... Since then I've recorded every single game I played, with MAME, and I finished uploading again here at MARP after more than a year. Not bad, in 24 hours I got from place 371st to 222nd :)

Personal challenge: have three first places before summer. I'm not going to dedicate full hours to MARP, but I am still good at tetris :twisted:

Posted: Mon May 27, 2002 1:20 am
by cosumel
> 100 - (100 - (your score / top score)) * (0.85 ^ (your place - 1))

Hmm. That seems too complicated. Isn't this easier. It is the way that I though it has been:

(your score/ high score) * (.85)^(place-1)

Your way=> 100-(100-(YS/TS)*(.85)^(rank-1) = 100-(100-(.944))*.85 = (100-99.156)*.85 = .944*.85 = .8028
My way => 92000/97400*.85 = .944*.85 = .8028

The same score, but easier.

What am I missing?[/quote]

Posted: Mon May 27, 2002 8:47 am
by gameboy9
Yeah, that's a simpler formula alright. :)